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Applies to:  

Status
colourGreen
titleCelonis 4.0
 
Status
colourGreen
titleCelonis 4.2
 
Status
colourGreen
titleCelonis 4.3
 
Status
colourGreen
titleCelonis 4.4
 

Description

Calculates the number of distinct elements in the specified column for each element of the given parent table.

PU_COUNT_DISTINCT can be applied on any data type. The data type of the result is always an INT.

If no value in the child table exists for the element in the parent table (either because all values of the child table column are filtered out, or because no corresponding value exists in the first place), 0 will be returned.

Syntax


Code Block
languagetext
themeDJango
PU_COUNT_DISTINCT ( parent_table, child_table.column [, filter_expression] )


Examples

Count the number of distinct values for each company code:


Panel
titleQuery
Column1


Code Block
languagetext
themeDJango
"companyDetail"."companyCode"


Column2


Code Block
languagetext
themeDJango
PU_COUNT_DISTINCT("companyDetail", "caseTable"."value")




Panel
titleInput
caseTable


caseId : INTcompanyCode : STRINGvalue : INT
1
'001'
600
2
'001'
400
3
'001'
200
4
'002'
300
5
'002'
300
6
'003'
200


companyDetail


companyCode : STRINGcountry : STRING
'001''DE'
'002''DE'
'003''US'



Foreign Keys


caseTable.companyCodecompanyDetail.companyCode




Panel
titleOutput
Result


Column1 : STRINGColumn2 : INT
'001'
3
'002'
1
'003'
1






Count the number of distinct values for each company code. Only consider cases with an ID larger than 2:


Panel
titleQuery
Column1


Code Block
languagetext
themeDJango
"companyDetail"."companyCode"


Column2


Code Block
languagetext
themeDJango
PU_COUNT_DISTINCT("companyDetail", "caseTable"."value", "caseTable"."caseID" > 2)




Panel
titleInput
caseTable


caseId : INTcompanyCode : STRINGvalue : INT
1
'001'
600
2
'001'
400
3
'001'
200
4
'002'
300
5
'002'
300
6
'003'
200


companyDetail


companyCode : STRINGcountry : STRING
'001''DE'
'002''DE'
'003''US'



Foreign Keys


caseTable.companyCodecompanyDetail.companyCode




Panel
titleOutput
Result


Column1 : STRINGColumn2 : INT
'001'
1
'002'
1
'003'
1






Count the number of distinct values for each company code. Only consider cases with an ID larger than 3. All case table values for companyCode '001' are filtered out, which means that in this case, 0 is returned:


Panel
titleQuery
Column1


Code Block
languagetext
themeDJango
"companyDetail"."companyCode"


Column2


Code Block
languagetext
themeDJango
PU_COUNT_DISTINCT("companyDetail", "caseTable"."value", "caseTable"."caseID" > 3)




Panel
titleInput
caseTable


caseId : INTcompanyCode : STRINGvalue : INT
1
'001'
600
2
'001'
400
3
'001'
200
4
'002'
300
5
'002'
300
6
'003'
200


companyDetail


companyCode : STRINGcountry : STRING
'001''DE'
'002''DE'
'003''US'



Foreign Keys


caseTable.companyCodecompanyDetail.companyCode




Panel
titleOutput
Result


Column1 : STRINGColumn2 : INT
'001'
0
'002'
1
'003'
1