Applies to: CELONIS 4.0 CELONIS 4.2 CELONIS 4.3 CELONIS 4.4 CELONIS 4.5 CELONIS 4.6
Description
Calculates the number of distinct elements in the specified column for each element of the given child table.
PU_COUNT_DISTINCT can be applied on any data type. The data type of the result is always an INT.
If no value in the parent table exists for the element in the child table (either because all values of the parent table column are filtered out, or because no corresponding value exists in the first place), 0 will be returned.
Syntax
PU_COUNT_DISTINCT ( child_table, parent_table.column [, filter_expression] )
PU_COUNT_DISTINCT ( DOMAIN_TABLE ( column1,...,columnN ), parent_table.column [, filter_expression] )
Examples
[1] Count the number of distinct values for each company code:
Query
Column1
"companyDetail"."companyCode"
Column2
PU_COUNT_DISTINCT("companyDetail", "caseTable"."value")
[2] PU functions can be used in a FILTER.
In this example, the company codes are filtered such that the corresponding distinct number of case table values is smaller than 2:
Query
Filter
FILTER PU_COUNT_DISTINCT ( "companyDetail", "caseTable"."value" ) < 2
Column1
"companyDetail"."companyCode"
[3] PU functions can be used inside another aggregation function.
In this example, the maximum value of all
distinct number of case table values for each company code is calculated:
Query
Column1
MAX ( PU_COUNT_DISTINCT ( "companyDetail", "caseTable"."value" ) )
[4] Count the number of distinct values for each company code. Only consider cases with an ID larger than 2:
Query
Column1
"companyDetail"."companyCode"
Column2
PU_COUNT_DISTINCT("companyDetail", "caseTable"."value", "caseTable"."caseID" > 2)
[5] Count the number of distinct values for each company code. Only consider cases with an ID larger than 3.
All case table values for companyCode '001' are filtered out, which means that in this case, 0 is returned:
Query
Column1
"companyDetail"."companyCode"
Column2
PU_COUNT_DISTINCT("companyDetail", "caseTable"."value", "caseTable"."caseID" > 3)
[6] For each case ID, calculate the number of distinct case table values for the associated company code using
DOMAIN_TABLE
:
Query
Column1
"caseTable"."caseId"
Column2
PU_COUNT_DISTINCT(DOMAIN_TABLE("caseTable"."companyCode"), "caseTable"."value")